Question

对数的平方lg25+2/3lg8+lg5×lg20+(lg2)我就是不会计最后一步(lg2)该怎么算,最后是（lg2)的

Answer 1

lg25 + (2/3)lg8 + lg5×lg20 + (lg2)²

= lg5² + (2/3)lg2³ + (lg5)×lg(2²×5) + (lg2)²

= 2lg5 + 2lg2 + 2(lg5)×(lg2) + (lg5)² + (lg2)²

= 2lg(5×2) + [(lg5) + (lg2)]²

= 2lg10 + [lg10]²

= 2 + 1

= 3