Question

[(x+2/x²-2x)-(x-1/x²-4x+4)]÷(x-4/x)

Answer 1

是[(x+2)/(x²-2x）-（x-1)/（x²-4x+4）]/[(x-4)/x]吧,=[(x+2)/x(x-2)-(x-1)/(x-2)²]×（x-4)/x=[(x+2)（x-2)-x（x-1）]/[x(x-2)²]×（x-4)/x={（x-4)/x(x-2)²]×(x-4)/x=1/(x-2)².