{an}前n项和Sn=n^2-4n+4,求和Tn=1/a1·a2+1/a2·a3+……1/an·an-1
1个回答
1/2*3=1/2-1/3
1/(An-1*An)=(An-An-1)/An-1-(An-An-1)/An
An等差数列都可以这么求和
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