Question

二次根式 (20 15:6:51)

Answer 1

∵x+3/x+2=1/√3+√2+1 ,

∴X+2/x+3=√3+√2+1 ,

即[(x+3)-1)/(x+3)==√3+√2+1

∴-1/(x+3)=√3+√2

x-3/2x-4÷(5/x-2 -x-2)

=(x-3)/2(x-2)÷(9-x^2)/(x-2)

=(x-3)/2(x-2)*(x-2)/(3+x)(3-x)

=-1/2*1/(x+3)

=(√3+√2)/2