Question

已知x y为不相同的 正数,是比较x的平方（x-y）与y的平方（x-y）的大小

Answer 1

[x^2(x-y)]-[y^2(x-y)]=(x^2-y^2)(x-y)=(x+y)(x-y)(x-y)=(x+y)(x-y)^2

x y为不相同的正数,x+y＞0,(x-y)^2＞0

(x+y)((x-y)^2＞0

[x^2(x-y)]-[y^2(x-y)]＞0

x^2(x-y)＞y^2(x-y)