S3=a1(1-q^3)/(1-q)=2(1-q^3)/(1-q)=14
所以(1-q^3)/(1-q)=7
(1-q)(1+q+q^2)/(1-q)=7
1+q+q^2=7
q^2+q-6=0
(q+3)(q-2)=0
q=-3或q=2