Question

不等式的解集(x-2)²>5 (x+1)²≤0 (x-4)²＞0 6x²+5x-

Answer 1

(x-2)²>5

x-2＞√5或x-2＜-√5;

x＞2+√5或x＜2-√5;

(x+1)²≤0

x+1=0;

x=-1;

(x-4)²＞0

x≠4;

6x²+5x-4＜0

6(x²+5x/6+25/144)-4-25/24＜0;

6(x+5/12)²＜121/24;

(x+5/12)²＜121/144;

-11/12＜x+5/12＜11/12

-4/3＜x＜1/2;

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