1.密度之比即为摩尔质量之比.所以密度是氢气的43倍即为摩尔质量是氢气的43倍,所以M=86g/mol.烷烃CnH2n+2可得n=6.所以A为C6H14
2.CnH2n+2燃烧:CnH2n+2 +(3n+1)/2 O2→nCO2 +(n+1)H2O
n=14,所以C为C14H30.
3.11.2L为0.5mol则(3n+1)/2 =5,则n=3.E为C3H8
1.密度之比即为摩尔质量之比.所以密度是氢气的43倍即为摩尔质量是氢气的43倍,所以M=86g/mol.烷烃CnH2n+2可得n=6.所以A为C6H14
2.CnH2n+2燃烧:CnH2n+2 +(3n+1)/2 O2→nCO2 +(n+1)H2O
n=14,所以C为C14H30.
3.11.2L为0.5mol则(3n+1)/2 =5,则n=3.E为C3H8