已知f(x)=2的x次幂,(x≥4) f(x)=f(x+2) ,(x

1个回答

  • 128/3

    解为:

    因为log0.5 3-2

    所以 log0.5 (0.5^2*3)<4 代入(2)得log0.5 (0.5^4*3)仍小于4

    所以代入(2)得log0.5 (0.5^6*3) > 4

    因为log0.5 3得值>-2 即 0.5^6*0.5^(-1.多) > 4

    0.5^(-1.多)为 log0.5 3这时代入(1)得

    2^[log0.5 (0.5^5*3)]=2^log0.5 (0.5^6) *2^log0.5 0.5*3

    2^log0.5 (0.5^5)=2^6=64

    2^log0.5 0.5*3=2^log1/2 3/2=2^log2 2/3

    log2 2/3=x 2^x=2/3

    2^log2 2/3=2^x

    因为2^x=2/3

    所以2^log2 2/3=2/3

    所以得128/3