已知：x2-y2=16,x+y=2,
求：（3x-3y）/（y2-x2）+（x2-2xy+y2）/（x2-y2）-（x2-x-6）/（x+2）
除以(x+y)
由x2-y2=16,x+y=2,可得：x-y=8;
则：：
（3x-3y）/（y2-x2）+（x2-2xy+y2）/（x2-y2）-（x2-x-6）/（x+2）/(x+y)
=24/16+64/16-(x-3)/2
=1.5+4-x/2+1.5
=7-x/2 .
已知：x2-y2=16,x+y=2,求：3x-3y/y2-x2+x2-2xy+y2/x2-y2-x2-x-6/x+2除以
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