Question

用乘法法则算导数补充图片

Answer 1

f'(x)=3[(2-x)^(2/3)]' *(8+x)^5 +3(2-x)^(2/3) *[(8+x)^5]'

=3*(2/3)(2-x)^(-1/3) *(-1)(8+x)^5 +3(2-x)^(2/3) *5(8+x)^4

=-2(2-x)^(-1/3) *(8+x)^5 +15(2-x)^(2/3) *(8+x)^4