Question

n的1次方+2次方+3次方…a次方,求这样的有什么公式?

Answer 1

给你一个较全的：

SN = 1^M + 2^M + 3^M + .+n^M M是自然数

M = 1 n(n+1)/2

M = 2 n(n+1)(2n+1)/6

M = 3 (n+1)^2n²/4

M = 4 n(n+1)(2n+1)(3n²+3n-1)/30

M = 5 (n²n+1)²(2n²+2n-1)/12

限