Question

q=2 log2a1+log2a2+log2a3+...+log2a10=25则a1+a2+a3+.+a10=

Answer 1

log2a1+log2a2+log2a3+...+log2a10

=log2(a1*a2*...*a10)

=log2(a1^10*q^45)

=10*log2a1+45*log2q=25

log2a1=(25-45)/10

a1=1/4

a1+a2+a3+.+a10

=a1*(q^0+q^1+...+q^9)

=a1*(1-q^10)/(1-q)

=1/4*(2^10-1)

=2^8-1/4

=256-0.25

=255.75