Question

解三元一次方程组,a+二分之一b=c,二分之一a-b-c=1,3a+b=-2

Answer 1

a+b/2=c.(1)

a/2-b-c=1.(2)

3a+b=-2.(3)

(1)-(2):

a/2+3b/2+c=c-1

a+3b=-2.(4)

由(3)(4)解得:

a=b=-1/2

则c=a+b/2=-3/4

(a,b,c)=(-0.5,-0.5,-0.75)

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