Question

y=ax^5+bx^3+cx-2,当x=-2时,y=6时;求当x=2时,y的值

Answer 1

y=ax^5+bx^3+cx-2,

当x=-2时,y=6时;

y=a2^5+b2^3+2c-2=6

a2^5+b2^3+2c=8

求当x=2时

y=ax^5+bx^3+cx-2

=-a2^5-b2^3-2c-2

=-(a2^5+b2^3+2c)-2

=-8-2

=-10