物理课本的宽度大约20cm=0.2m,厚度大约1cm=0.01m,
质量大约300g=0.3kg,所以受到的重力大约G=mg=0.3kg×10N/kg=3N,
课本对桌面的压强大约为:
P=
F
S =
G
S =
3N
0.2m×0.01m =1500Pa,接近2000Pa.
故选C.
物理课本的宽度大约20cm=0.2m,厚度大约1cm=0.01m,
质量大约300g=0.3kg,所以受到的重力大约G=mg=0.3kg×10N/kg=3N,
课本对桌面的压强大约为:
P=
F
S =
G
S =
3N
0.2m×0.01m =1500Pa,接近2000Pa.
故选C.