﹙1+0.112+0.123﹚×﹙0.112+0.123+0.134﹚-﹙1+0.112+0.123+0.134﹚×﹙0
1个回答
设 0.112+0.123=a
原式=﹙1+a﹚×﹙a+0.134﹚-﹙1+a+0.134﹚×a
=a+a²+0.134a+0.134 - (a+a²+0.134a)
=0.134
相关问题
(0.1+0.12+0.123+0.1234)*(0.12+0.123+0.1234+0.12345)-(0.1+0.1
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(100+0.123+0.245+8.9)x(0.123+0.245+8.9+12.71)-(100+0.123+0.2
124×0.456-123×0.455怎样用简便算法
(0.125+0.234+0.345)×(0.234+0.345+0.456)减(0.123+0.234+0.345+0
简算 0.123+2.66+0.86 (3.26+2.6)×(1-0.75)
123+123+12-147+0-0-85+45-42+12-23=
(1)1.9×130%= (2)0.3×100%=(3)16×100%=(4)15×18.0%= (5)9×112%=
1.23×45.6×0.789÷4.56÷7.89÷0.123=(简便运算)
0.123+0.321+0.234+0.432+0.345+0.543+……+0.789+0.987=?