y*(y+1)*(y+2)*(y+3)=360
(y^2+3y)*(y^2+3y+2)=360
设y^2+3y=x
则x*(x+2)=360
x^2+2x-360=0
(x-18)*(x+20)=0
x=18或-20
因为y>0
所以y^2+3y=18
y^2+3y-18=0
(y-3)*(y+6)=0
所以y=3或-6
y*(y+1)*(y+2)*(y+3)=360
(y^2+3y)*(y^2+3y+2)=360
设y^2+3y=x
则x*(x+2)=360
x^2+2x-360=0
(x-18)*(x+20)=0
x=18或-20
因为y>0
所以y^2+3y=18
y^2+3y-18=0
(y-3)*(y+6)=0
所以y=3或-6