x^2-7x-8=(x-8)*(x+1)>0 所以x>8或x
不等式几个问题x^2-7x-8>0x^2+11-125(x-3)/8-1
1个回答
相关问题
-
(-0.125)^12x(-1又2/3)^7x(-8)^13x(-3/5)^9
-
(x-1)^2=36 8(x-3)^3+125=0
-
1/x2+11x-8+1/x2+2x-8+1/x2-13x-8=0
-
解方程 (1)x+ 2 3 = 4 5 (2)x- 7 8 = 1 4 (3) 1 6 -2x=0.125.
-
0.625x...(8个0.625)x0.625x8x...(7个8)x8x2x2x...(6个2)x2
-
X+25%X=2.8 (1-60%)X=0.32 125%X-X=44 1-40%X=0.7.
-
(125/1+0.8)x1.25 (方法) 9/7x11/5+9/5x11/1 (方法)
-
(2012•桃源县)解方程. [3/8]-5x=0.125 x:0.2=[5/8] 12X+7×0.3=20.1
-
解方程.2x+17=35 3x-64=11 12+8x=52 0.8x-4.2=2.2 14x-x=169 1.7x+0
-
5.5x+6.7=7.8 28-x+3.6=20 3.5x-0.8x=11.34 8x-27.54÷2.7=1.8 6.