Question

请你说明“两个连续奇数的平方差是8的倍数”详细

Answer 1

设两个连续的奇数为2n+1,2n+3,

（2n+3）^2-（2n+1）^2

=4n^2+12n+9-(4n^2+4n+1)

=8n+8

=8(n+1)

所以其差一定是8的倍数