x²-3x+3=(x-2)²+x-1=(x-2)²+(x-2)+1
y=(x²-3x+3)/(x-2)
=(x-2)+1+1/(x-2)
>=2√[(x-2)×1/(x-2)]+1 (当且仅当(x-2)=1/(x-2),即x=3时取等)
=3
所以,y的最小值为3
x²-3x+3=(x-2)²+x-1=(x-2)²+(x-2)+1
y=(x²-3x+3)/(x-2)
=(x-2)+1+1/(x-2)
>=2√[(x-2)×1/(x-2)]+1 (当且仅当(x-2)=1/(x-2),即x=3时取等)
=3
所以,y的最小值为3