1.∵BD⊥AA1,BD⊥AC
AA1∩AC=面AA1C1C
∴BD⊥面AA1C1C
又BD∈面A1BD
∴面A1BD⊥面AA1C1C
2.∵O是BD中点,M是A1B中点
∴MO是△A1BD的中位线
∴MO∥A1D
又A1D∥面BCC1B1
∴MO∥面BCC1B1
1.∵BD⊥AA1,BD⊥AC
AA1∩AC=面AA1C1C
∴BD⊥面AA1C1C
又BD∈面A1BD
∴面A1BD⊥面AA1C1C
2.∵O是BD中点,M是A1B中点
∴MO是△A1BD的中位线
∴MO∥A1D
又A1D∥面BCC1B1
∴MO∥面BCC1B1