(1)设需要这种双氧水的质量为x,则:
x * 10% = 1500g * 3%
得:x = 450g
(2)设已经分解的过氧化氢的质量为y,则:
2H2O2 = 2H2O + O2↑
68 32
y =32y/68
(1000g * 30% - y) / (1000g - 32y/68) * 100% = 10%
得:y = 209.9g
答:………………………………………………
(1)设需要这种双氧水的质量为x,则:
x * 10% = 1500g * 3%
得:x = 450g
(2)设已经分解的过氧化氢的质量为y,则:
2H2O2 = 2H2O + O2↑
68 32
y =32y/68
(1000g * 30% - y) / (1000g - 32y/68) * 100% = 10%
得:y = 209.9g
答:………………………………………………