y=√3sin（2x-∏/6）+2sin^2（x-∏/12）如何化简
1个回答
原式=√3sin(2x-∏/6)+1-cos（2x-∏/6)
=2sin(2x-∏/6-∏/6)+1
=2sin(2x-∏/3)+1
相关问题
f（x）=6cos²x-√3sin2x 如何化简?
化简y=sin^2(x)+2sin(x)cos(x)+3cos^2(x)
2sin2x*cos2x如何化简为-2sin4x
化简 sin²x+sin²(x+2π/3)+sin²(x-2π/3)
化简y=2sin(x/2+π/3)
化简sinx+ sin2x/2+ sin3x/3
y=1-2sin^2 x如何化简成cos2x的?
sin2(x/2-π/12)化简,
1+sin^2x)^1/2-1如何化简为1/2sin^2x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x