Question

当x=2时,y=2008,代数式x2+2xy+y2/x2+y2乘以x-y/x2+xy的值= x2为x的平方

Answer 1

x2+2xy+y2/x2-y2乘以x-y/x2+xy

=(x+y)^2/(x+y)(x-y)*(x-y)/(x(x+y))

=1/x

=1/2