√(x+2) +y^2-2√(3y）+3
=√(x+2)+(y-√3)^2=0
所以x=-2,y=√3
xy=-2√3
因为2-x≥0且x-2≥0,所以x=2,y=4
(xy)^1/2=2√2
若实数x,y满足√(x+2) +y^2-2√(3y）+3=0,则xy的值是?
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