Question

(x+1)(x+2)(x+3)(x+4)-24

Answer 1

原式=[(x+1)(x+4)][(x+2)(x+3)]-24 =(x^2+5x+4)(x^2+5x+6)-24 设y=x^2+5x =(y+4)(y+6)-24=y^2+10y+24-24=y^2+10y =y(y+10) =(x^2+5x)(x^2+5x+10) =x(x+5)(x^2+5x+10) 此题运用分组分解方法,希望采纳啊!