Question

如图,已知AB=AC,BD,CE分别是∠ABC,∠ACB的平分线,AM⊥BD于M,AN⊥CE于N,说明△AMN是等腰三角

Answer 1

AB=AC,∠ABC=∠ACB

BD,CE分别是∠ABC,∠ACB的平分线,∠ABD=∠ACE,

△ABD≌△ACE,AE=AD,∠MDA=∠NEA

AM⊥BD于M,AN⊥CE于N,∠AMD=∠ANE=Rt∠

△ANE≌△AMD,AN=AM,

所以,△AMN是等腰三角