Question

已知a=根号3 +1 b=根号3 -1,求(a^2+2ab+b^2)/(a^2 - b^2)

Answer 1

(a^2+2ab+b^2)/(a^2 - b^2)

=(a+b)²/[(a+b)(a-b)]

=(a+b)/(a-b)

当a=根号3 +1 b=根号3 -1时

原式=（√3+1+√3-1）/（√3+1-√3+1）

=2√3÷2

=√3