甲、乙两位同学将一个2次3项式分解因式,甲同学因看错了一次项系数,而分解成2(x-1)(x-9);乙同学因为看错了常数项

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  • 2(x-1)(x-9)

    =2(x^2-10x+9)

    =2x^2-20x+18

    2(x-2)(x-4)

    =2(x^2-6x+8)

    =2x^2-12x+16

    原多项式应为:2x^2-12x+18

    =2(x^2-6x+9)

    =2(x-3)^2