(1)5和7的最小公倍数是35,
因为存书的本数在60~100本,则应为:35×2=70(本);
答:书架上存书70本;
(2)设电高峰时段用电x千瓦时的电费,
0.61×x+(100-x)×0.30,
=0.61x+30-0.3x,
=0.31x+30(元),
答:他家6月份需付电费0.31x+30元,
故答案为:70;0.31x+30.
(1)5和7的最小公倍数是35,
因为存书的本数在60~100本,则应为:35×2=70(本);
答:书架上存书70本;
(2)设电高峰时段用电x千瓦时的电费,
0.61×x+(100-x)×0.30,
=0.61x+30-0.3x,
=0.31x+30(元),
答:他家6月份需付电费0.31x+30元,
故答案为:70;0.31x+30.