Question

祥细步骤acosC＋根号3asinC－b－c＝0

Answer 1

一问：sinAcosC＋√3sinAsinC－sinB－sinC=0

sinAcosC＋√3sinAsinC－sin(A＋C)－sinC=0

sinAcosC＋√3sinAsinC－sinAcosC－cosAsinC－sinC=0

√3sinAsinC－cosAsinC－sinC=0

√3sinA=1＋cosA

因tan(A/2)=(sinA)/(1＋cosA)=√3/3

得：A/2=30°,即A=60°

二问：S＝1/2 * bcsinA,由一问可知sinA=√3/2,所以bc=4