1/根号3+1+1/根号5+根号3+1/根号7+根号5……1/根号2n+1+根号2n-1
=(1/2)[√3-1+√5-√3+√7-√5+……+√（2n+1）-√(2n-1)]
=(1/2)(√（2n+1）-1)
,把2013带入即可
原式=(√3-1)/2+(√5-√3)/2+(√7-√5)/2+……+[√(2n+1)-√(2n-1)]/2
=[√3-1+√5-√3+√7-√5+……+√(2n+1)-√(2n-1)]/2
=[√(2n+1)-1]/2
化简1/√3+1+1/√5+√3+1/√7+√5+……+1/√2013+√2011
1个回答
相关问题
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数学题1/1*3+1/3*5+1/5*7+1/7*9+.1/2011*2013 =
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1+3+5+7+.+2011+2013
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1/3×5+1/5×7+1/7×9.+1/2011×2013
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1/√3+1+1/√5+√3+1/√7+√5+至=1/√2n+1+√2n-1.化简
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1/1x3+1/3x5+1/5x7.1/2009x2010+1/2011x2013
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化简1/log 7+1/log 7+1/log 7 5 3 2
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1*3/1+3*5/1+5*7/1+...+2009*2011/1
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1*3/1+3*5/1+5*7/1+···+2013*2015/1=?
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1/(1*3)+1/(3*5)+1/(5*7)+.1/(2013*2015)