[(x-2)*3-(x-1)*2+1]/x-2
=[(x-2)³-x(x-2)]/(x-2)
=x²-4x+4-x
=x²-5x-2000+2004
=2004
已知x*2-5x-200=0,求[(x-2)*3-(x-1)*2+1]/x-2
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