Question

x等于-2,y等于1/2,求x的2次方乘x的2n次方乘（y的n-1次方）的平方的值

Answer 1

x=-2 ,y=1/2 ,xy=-1

x^2×x^(2n)×[y^(n-1)]^2

=x^2×[x^2×x^(2n-2)]×y^(2n-2)

=x^4×(xy)^(2n-2)

=(-2)^4×[(xy)^2]^(n-1)

=16*1

=16