解由a的平方+b的平方-4a-2b+5=0
即(a-2)²+(b-1)²=0
即a=2,b=1
即(根号a+根号b)/(3根号a-2根号b)
=(根号2+根号1)/(3根号2-2根号1)
=(根号2+1)/(3根号2-2*1)
=(√2+1)/(3√2-2)
=(√2+1)(3√2+2)/(3√2-2)(3√2+2)
=(6+2√2+3√2+2)/14
=(5√2+8)/14
解由a的平方+b的平方-4a-2b+5=0
即(a-2)²+(b-1)²=0
即a=2,b=1
即(根号a+根号b)/(3根号a-2根号b)
=(根号2+根号1)/(3根号2-2根号1)
=(根号2+1)/(3根号2-2*1)
=(√2+1)/(3√2-2)
=(√2+1)(3√2+2)/(3√2-2)(3√2+2)
=(6+2√2+3√2+2)/14
=(5√2+8)/14