计算:4(m-1)^2+(2m+5)(5-2m)
2个回答
4(m-1)^2+(2m+5)(5-2m)
=4(m-1)^2-(2m+5)(2m-5)
=4m^2-8m+4-(4m^2-25)
=-8m+29
相关问题
计算4m+5m-m^4*m^5 3^3*3^(m-1)*3^(2m-2)+3^3m
计算 1/(m²-m)+(m-5)/(2m²-2)=?
计算:(5/6)m·(4/5)m·(3/4)m·(2/3)m·(6/2)m
1/(m^2-m)+(m-5)/(2m^2-2) 分式计算
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
计算 (-2m-1)(-2m-1) (4x-3m)(4x-3m) (1.5a-2/3b)(1.5a-2/3b)
计算这道题 (2m²+4m-3)+(5m+2)
(1)M^2+M-3M^2-5M+2M^2+4=?(M=-3/4)
计算:(2m+1/2)(4m-1)(4m∧2-1/4)-4m∧2(2m+1)(2m-1)
计算:(m+3m+5m+……2013m)-(2m+4m+6m+…2012m)=_