解
lim(x→1)(x²-2x+1)/(x²-1)
=lim(x→1)(x-1)²/(x-1)(x+1)
=lim(x→1)(x-1)/(x+1)
=(1-1)/(1+1)
=0
lim(x→0)sin3x/x
=3lim(x→0)sin3x/3x
=3
y=x³lnx
y'=(x³lnx)'
=(x³)'lnx+x³(lnx)'
=3x²lnx+x³/x
=3x²lnx+x²
y‘=dy/dx=[(3x+1)]^5'
=5(3x+1)^4
这个该怎么解答?最好是步骤齐全
解
lim(x→1)(x²-2x+1)/(x²-1)
=lim(x→1)(x-1)²/(x-1)(x+1)
=lim(x→1)(x-1)/(x+1)
=(1-1)/(1+1)
=0
lim(x→0)sin3x/x
=3lim(x→0)sin3x/3x
=3
y=x³lnx
y'=(x³lnx)'
=(x³)'lnx+x³(lnx)'
=3x²lnx+x³/x
=3x²lnx+x²
y‘=dy/dx=[(3x+1)]^5'
=5(3x+1)^4