Question

在等比数列{an}中,log2a1+log2a2+.+log2a10=35

Answer 1

log2a1+log2a2+.+log2a10=35

=>a1a2……a10=2^35

a1^10*2^((1+10)*10/2)=2^35

a1=1/4

a1+a2+……+a10=a1(1-q^10)/(1-q)=(1/4)(1-2^10)/(1-2)=1023/4