Question

取纯铝片4.05g放入0.5mol/L的氢氧化钠溶液500毫升中,充分反应后...

Answer 1

n(Al)=4.05/27=0.15mol

n(NaOH)=0.5*0.5=0.25mol

(1)V(H2)=22.4*0.15*3/2=5.04L

(2)n(HCl)=18.25%*80/36.5=0.4mol

n[HCl]=0.4-(0.25-0.15)=0.3mol(与NaAlO2反应)

m[Al(OH)3]=78*(0.15-0.15/3)=7.8g