数学归纳法：
当n=2时，有1/3*4/3=4/9>1/2*3/4=3/8
假设当n=K时成立；则有1/(k+1)(1+1/3+1/5+...+1/2k-1)>1/k*(1/2+1/4+...+1/2k)
则1/(k+2)*(1+1/3+...1/2k+1)
>(k+1)/(k+2)*1/k(1/2+.....
求证：1/(n+1)*(1+1/3+1/5+...+1/2n-1)>1/n*(1/2+1/4+1/6+...+1/2n)
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