y=x+3/5x-1 求值域

1个回答

  • y=(5x-1)/(4x+2)=(5x+5/2-7/2)/(4x+2)=(5x+5/2)/(4x+2)-7/[2(4x+2)]=5/4-7/(8x+4)因为7/(8x+4)不等于0y=5/4-7/(8x+4)不等于5/4所以y=(5x-1)/(4x+2)的值域为y不等于5/4