弦长2200,弧高300,R2166.5求弧长

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  • 弦长L=2200,弧高H=300,求弧长C?

    弧半径为R,弧所对的圆心角为A.

    R^2=(R-H)^2+(L/2)^2

    R^2=R^2-2*R*H+H^2+L^2/4

    2*R*H=H^2+L^2/4

    R=H/2+L^2/(8*H)

    =300/2+2200^2/(8*300)

    =2166.67

    A=2*ARC SIN((L/2)/R)

    =2*ARC SIN((2200/2)/2166.67)

    =61.02度

    =61.02*PI/180

    =1.065弧度

    C=A*R=1.065*2166.67=2307.52

    弦长L=2200,R=2166.5,求弧长C?

    A=2*ARC SIN((L/2)/R)

    =2*ARC SIN((2200/2)/2166.5)

    =61.03度

    =61.03*PI/180

    =1.0651弧度

    C=A*R=1.0651*2166.5=2307.54