z=V2(cosx+isinx),所以2sin2x=2,2x=π/2+2kπ,x=π/4,5π/4(其余点不变)
1)x=π/4,z=1+i,z^2=2i,z-z^2=1-i,S=1/2*(1+1)*1=1
2)x=5π/4,z=-1-i,z^2=2i,z-z^2=-1-3i,S=1/2*(3-1)*1=1
S=1
z=V2(cosx+isinx),所以2sin2x=2,2x=π/2+2kπ,x=π/4,5π/4(其余点不变)
1)x=π/4,z=1+i,z^2=2i,z-z^2=1-i,S=1/2*(1+1)*1=1
2)x=5π/4,z=-1-i,z^2=2i,z-z^2=-1-3i,S=1/2*(3-1)*1=1
S=1