弦长L=32米弧高H=6米,求弧长C?
弧半径为R,弧所对的圆心角为A.
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=6/2+32^2/(8*6)
=24.333米
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((32/2)/24.333)
=82.224度
=82.224*PI/180
=1.43508弧度
C=R*A=24.333*1.43508=34.92米
弦长L=32米弧高H=6米,求弧长C?
弧半径为R,弧所对的圆心角为A.
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=6/2+32^2/(8*6)
=24.333米
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((32/2)/24.333)
=82.224度
=82.224*PI/180
=1.43508弧度
C=R*A=24.333*1.43508=34.92米