过F作FM垂直AB于M,三角形AMF,AOB相似,得
|FM|/|AO|=|AF|/|AB|,即(b/√7)/b=(a-c)/√(a^2+b^2)=√7
7(a-c)^2 = a^2 +b^2 = 2a^2 -c^2
5a^2 -14ac+8c^2 = 0 (5a-4c)(a-2c)=0
a = 4c/5 (椭圆a>c,舍去) a = 2c 所以 e = 1/2
过F作FM垂直AB于M,三角形AMF,AOB相似,得
|FM|/|AO|=|AF|/|AB|,即(b/√7)/b=(a-c)/√(a^2+b^2)=√7
7(a-c)^2 = a^2 +b^2 = 2a^2 -c^2
5a^2 -14ac+8c^2 = 0 (5a-4c)(a-2c)=0
a = 4c/5 (椭圆a>c,舍去) a = 2c 所以 e = 1/2