tanθ=sinθ/cosθ=5/4
cosθ=(4/5)sinθ
因为:sin²θ+cos²θ=1
则:sin²θ+(16/25)sin²θ=1
sin²θ=25/41
sinθ=±5√41/41
cosθ=±4√41/41
所以:
(1)sinθ=5√41/41;cosθ=4√41/41
(2)sinθ=-5√41/41;cosθ=-4√41/41
tanθ=sinθ/cosθ=5/4
cosθ=(4/5)sinθ
因为:sin²θ+cos²θ=1
则:sin²θ+(16/25)sin²θ=1
sin²θ=25/41
sinθ=±5√41/41
cosθ=±4√41/41
所以:
(1)sinθ=5√41/41;cosθ=4√41/41
(2)sinθ=-5√41/41;cosθ=-4√41/41