log(√2+1)(3+2√2)+log√3（√6

log(√2+1)(3+2√2)+log√3（√6+3√3）-log3(2+√3)=

1个回答

原式=log(√2+1)[(√2+1)²]+log3[(√6+3√3)²÷(2+√3)]
=2log(√2+1)(√2+1)+log3[(33+12√2)÷(2+√3)]
=2+log3[(33+12√2)/(2+√3)]
你写错了