Question

{x+2y=3,x-2y=1,2x+3y+z=6.5(解三元一次方程组) {x+y+z=1,x+3y+7z=-1,x+5

Answer 1

1

前两个方程式解得x=2,y=0.5

带入第三个得z=1

2

x=1-y-z=-1-3y-7z=2-5y-8z

即{2y+6z=-2,2y+z=3得y=2,z=-1

带入x=1-y-z=0,故x=0