U/I=|Z|,
|Z|=√(R²+X²)=√[R²+(2πfL)²
所以 U/I=√[R²+(2πfL)²],即(U/I)²=R²+(2πfL)².
代入数据得:
(100/15)²=R²+(2π×50×L)²,
(100/10)²=R²+(2π×100×L)².
解得 R =5.09Ω,L=0.0137H.
U/I=|Z|,
|Z|=√(R²+X²)=√[R²+(2πfL)²
所以 U/I=√[R²+(2πfL)²],即(U/I)²=R²+(2πfL)².
代入数据得:
(100/15)²=R²+(2π×50×L)²,
(100/10)²=R²+(2π×100×L)².
解得 R =5.09Ω,L=0.0137H.